Math, asked by akhil6752, 1 year ago

form the equation where roots are 3-√3i whole upon / 2 and 3+√3i whole upon / 2​

Answers

Answered by AnonymousKSB
0

Answer:

x2-3x+3

Step-by-step explanation:

product of roots=-b/a

3-√3i whole upon / 2 × 3+√3i whole upon / 2=c/a

3=c/a

sum of roots=-b/a=3-√3i whole upon / 2 + 3+√3i whole upon / 2

3=-b/a

now equation will be:x2-(sum of roots)x+(product of roots)

=x2-3x+3

Similar questions