Form the equation whose roots are 1-3i , 1+3i
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Answer:
for forming any quadratic equation given its roots use;
(x-a)(x-b)__(1)
where a and b are roots of that equation
Step-by-step explanation:
here,
keep a=1-3i and b=1+3i in equation (1)
you'll get
(x-(1-3i))(x-(1+3i))
(x-1+3i)(x-1-3i)
x^2-x-x3i-x+1+3i+x3i-3i-9i^2
x^2-2x+1+9_____(as we know square of iota is-1)
x^2-2x+10 answer
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