Question

form the equation whose roots are 2±
$\sqrt{3}$
and 1±2i​

Answer 1

Answer:

Step-by-step explanation:

(X-(2+√3)),(x-(2-√3)),(x-(1+i)),(x-(1-i)) are the factors of the required equation.

Then equation:(x-2-√3)(x-2+√3)(x-1-2i)(x-1+2i)=0