Math, asked by dipikabarot2309, 7 hours ago

Form the largest seven digit number using the digits 3,8,1,0,9,2,6, and check whether it is divisible to 6,10,11,15​

Answers

Answered by DeekshantSharma9
2

Answer:

Largest number is 9863210. It is divisible by 10, and it is not divisible by 6, 11 and 15.

Step-by-step explanation:

Largest Number = Descending order

= 9863210

Divisibility by 6 = Sum of digits should be divisible by 3 and units digit should be even

Units digit = 0 is even

9+8+6+3+2+1+0 = 29

29 is not divisible by 3.

9863210 is not divisible by 6.

Divisibility by 10 = Units digit should be 0

Units digit = 0

9863210 is divisible by 10.

Divisibility by 11 = Sum of odd digits - Sum of even digits = should be multiple of 11

Sum of odd digits = 9+6+2+0 = 17

Sum of even digits = 8+3+1 = 12

17 - 12 = 5 (not divisible by 11)

9863210 is not divisible by 11

Divisibility by 15 = Units digit should be 0 or 5 and should be divisible by 3

9863210 is not divisible by 3.

9863210 is not divisible by 15.

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