Question

Form the pair of linear equations for the following problem:
The difference between the two numbers is 48 and one number is three times the other.​

Answer 1

Answer:

Let the two numbers be x and y

x−y=26 …………(1)

x=3y ………..(2)

Substituting (2) in (1), we get

3y−y=26

2y=26

y=13

x=3y

x=3×13=39

∴ The two numbers are 39 and 13

Answer 2

$\fbox\orange{Solution}$

$\large{\sf{Let~the~no.~be~x}}$

$\large{\sf{So,~other~no.~=~3x}}$

${\sf\bold{There~difference~is~48}}$

${\sf{\color{maroon}{So,~we~can~say}}}$

$\large{\sf{3x~-~x~=~48}}$

$\large{\sf{2x~=~48}}$

$\large{\sf{x~=~\frac{48}{2} }}$

$\large{\sf{x~=~24}}$

${{\bold{\textsf{\textbf{\color{purple}{VERIFICATION}}}}}}$

We need to put x = 24 in statement 3x - x = 48

3 × 24 - 24 = 48

72 - 24 = 48

48 = 48

${\sf\bold{L.H.S~=~R.H.S}}$

${\sf\bold{Hence~verified}}$

____________________________

.°. Linear equation will be 3x - x = 48