Question

form the quadratic equation from the root 3 and -10​

Answer 1

let alpha nd beeta be 3 nd -10 respectively.....

now....

alpha + beeta = 3 + (-10)

= 3 - 10

= -7

alpha × beeta = 3 (-10)

= -30

x² - ( alpha + beeta)x + alpha × beeta

= x² - (-7)x + (-30)

= x² + 7x - 30