form the quadratic equation if it (√2+√3) & (√2-√3)
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Three consecutive integers are such that when they are taken in increasing order and multiplied by 2, 3, and 4 respectively, they add up to 74. Find these numbers.
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Answer:
Let x=3+
2
or x=3−
2
are the roots of a quadratic equation.
∴ x−(3+
2
)=0 or x−(3−
2
)=0
⟹ (x−(3+
2
))(x−(3−
2
))=0
⟹ (x
2
−x(3−
2
)−x(3+
2
)+(3+
2
)(3−
2
))=0
⟹ (x
2
−3x+x
2
−3x−x
2
+9−2)=0
⟹ (x
2
−6x+7)=0
Hence (x
2
−6x+7)=0 is the quadratic equation having roots 3+
2
and 3−
2
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