Question

Form the quadratic equation if its roots
are 3 and -1​

Answer 1

Answer:

To find-Equation

Step-by-step explanation:

Alpha=3 and Beta = -1

x^2-(Alpha+Beta)*x+ (a*b)

=>x^2-(3-(-1))*x+(3*-1)

=>x^2-4x-3

Hope this will help you

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Answer 2

Given roots are 3 and -1

therefore sum of zeroes =3+-1=2

product of zeroes=3×-1=-3

p(x)=k{x²-(sum of zeroes)+(product of zeroes)}

=k{x²-2x+(-3)}

=1(x²-2x-3) (where k=1)

therefore quadratic equation with roots is x²-2x-3

Hope It Helps You