Question

form the quadratic equation whose roots 2,-3​

Answer 1

Answer:

x^2+x-6=0

Step-by-step explanation:

x=2, x=-3

(x-2)(x+3)=0

x^2+x-6=0

Answer 2

$\displaystyle\huge\red{\underline{\underline{Solution}}}$

TO DETERMINE

A quadratic equation whose

roots are 2 and - 3 respectively

FORMULA TO BE IMPLEMENTED

The quadratic equation whose zeroes are given can be written as

$\sf{}{x}^{2} - (sum \: of \: the \: roots)x + (product \:of \: the \: roots) = 0$

EVALUATION

The required Quadratic Equation is

$\sf{}{x}^{2} - (sum \: of \: the \: roots)x + (product \:of \: the \: roots) = 0$

$\implies \sf{} {x}^{2} - ( 2 - 3)x + (2 \times - 3) = 0$

$\implies \sf{} {x}^{2} + x - 6= 0$

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ADDITIONAL INFORMATION

A general equation of quadratic equation is

$a {x}^{2} + bx + c = 0$

Now one of the way to solve this equation is by SRIDHAR ACHARYYA formula

For any quadratic equation

$a {x}^{2} + bx + c = 0$

The roots are given by

$\displaystyle \: x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac } }{2a}$

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