Math, asked by sreeraj5539, 1 year ago

Form.The quadratic equation whose roots are -2/3 and 4/5

Answers

Answered by yogendra55
6

Right answer in photo

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Answered by wifilethbridge
2

The required equation is x^2-\frac{22}{15}x+\frac{8}{15}=0

Step-by-step explanation:

We are given that the roots are -2/3 and 4/5

So (x+(\frac{-2}{3})=0and (x-\frac{4}{5})=0 are the roots

So,  (x+(\frac{-2}{3})(x-\frac{4}{5})=0

x(x+(\frac{-2}{3}))+(-\frac{4}{5})(x+(\frac{-2}{3})=0

x^2-\frac{2}{3}x-\frac{4}{5}x+\frac{8}{15}=0

x^2-\frac{22}{15}x+\frac{8}{15}=0

Hence The required equation is x^2-\frac{22}{15}x+\frac{8}{15}=0

#Learn more:

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