Question

form the quadratic equation whose roots are 2 + √5 and 2 - √5.
Pls it's urgent

Answer 1

Heya,

According to the question,

Roots of quadratic equation are 2 + √5 and 2 - √5

Let α = 2 + √5
ß = 2 - √5

Sum of zeros of polynomial = α + ß
= 2 + √5 + 2 - √5
= 2 + 2
= 4

Product of zeros of polynomial = αß
= (2 + √5)(2 - √5)
= 4 - 5
= -1

Quadratic polynomial = k(x² - (α + ß)x + αß)

=> k(x² - 4x - 1)

'k' is constant.

Hope this helps....:)

Answer 2

Answer:

BRAILNLEST ANSWER

Step-by-step explanation:

Correct option is

B

x

2

−4x−1=0

One root of the equation is 2+

5

. So, the next root will be 2−

5

∴ x=2+

5

and x=2−

5

∴ (x−(2+

5

))(x−(2−

5

))=0

∴ (x

2

+(4−5)−2x−

5

x−2x+

5

x)=0