Form the quadratic
equation whose roots are m/n and-n/m
Answers
Answered by
24
Answer:
Let the roots be α,β then quadratic equation will be
x² -(α + β)x + αβ = 0
Here,
α = m/n
β = -n/m
∴ Quadratic equation is,
= x² - (m/n - n/m)x + (m/n)(-n/m) =0
= x² - {(m²-n²)/mn}x -1 =0
= mnx² - (m²-n²)x - mn = 0
∴ ANSWER IS mnx² - (m²-n²)x - mn = 0
HOPE THIS HELPS YOU>>>>
PLZ MARK AS BRAINLEST/.............
Answered by
2
Answer:
Let the roots be α,β then quadratic equation will be
x² -(α + β)x + αβ = 0
Here,
α = m/n
β = -n/m
∴ Quadratic equation is,
= x² - (m/n - n/m)x + (m/n)(-n/m) =0
= x² - {(m²-n²)/mn}x -1 =0
= mnx² - (m²-n²)x - mn = 0
∴ ANSWER IS mnx² - (m²-n²)x - mn = 0
HOPE THIS HELPS YOU>>>>
pls brainliest
Step-by-step explanation:
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