Math, asked by sandinenivenkateshwa, 10 months ago

Form the quadratic
equation whose roots are m/n and-n/m

Answers

Answered by REDPLANET
24

Answer:

Let the roots be α,β then quadratic equation will be

x² -(α + β)x + αβ = 0

Here,

α = m/n

β = -n/m

∴ Quadratic equation is,

= x² - (m/n - n/m)x + (m/n)(-n/m) =0

= x² - {(m²-n²)/mn}x -1 =0

= mnx² - (m²-n²)x - mn = 0

∴ ANSWER IS  mnx² - (m²-n²)x - mn = 0

HOPE THIS HELPS YOU>>>>

PLZ MARK AS BRAINLEST/.............

Answered by lemawiperes1
2

Answer:

Let the roots be α,β then quadratic equation will be

x² -(α + β)x + αβ = 0

Here,

α = m/n

β = -n/m

∴ Quadratic equation is,

= x² - (m/n - n/m)x + (m/n)(-n/m) =0

= x² - {(m²-n²)/mn}x -1 =0

= mnx² - (m²-n²)x - mn = 0

∴ ANSWER IS  mnx² - (m²-n²)x - mn = 0

HOPE THIS HELPS YOU>>>>

pls brainliest

Step-by-step explanation:

.

Similar questions