Question

form the quadratic equation with the sum and product of its zeroes are -1/3 and -1/3respectively ​

Answer 1

Answer:

condition of giving product and sum in quadratic eqn. is..

x^2-(sum)x+(product)=0

now put sum and product in this eqn.

I.e.

3x^2+x-1=०

Answer 2

Step-by-step explanation:

given sum pf zeroes = -1/3

product of zeroes= -1/3

p(x)= k(x^2-(sum of zeroes)x+ product of zeroes)

p(x) =k(x^2-(-1/3)x+(-1/3))

p(x)= k(x^2+1/3x-1/3)

p(x)= k(3x^2+x-1/3)

k = 3

p(x)= 3x^2+x-1

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