Question

form the quadratic polynomial of _5 and _3​

Answer 1

Answer:

hey mate

if the zeroes of a quadratic polynomial are 5 and 3 then here is the solution.

à=5 ß=3

à+ß=5+3

= -8/1= -b/a

à×ß=15/1 = c/a

polynomial= px²-qx+t (let)

p=1

q=8

t=15

p(x)=x²-8x+15

OR

K{x²-(sum of zeroes)x+(product of zeroes)}

K(x²-8x+15)

where K is constant

this is the another method

may help you dear....✌️