Question

form the quadratic polynomial whoes zeroes are given below 3+√7 and 3-√7​

Answer 1

Answer:

sum of zeroes = (3+√7) + (3-√7) = 3+3+√7-√7 = 6

product of zeroes = (3+√7)(3-√7) = 9-7 = 2

now in ax² + bx + c,

let a be 1.

-b/a = 6

-b/1 = 6

-b = 6

b = -6

next

c/a = 2

c/1 = 2

c = 2

the quadratic equation becomes

x²-6x+2

Answer 2

Answer:

Step-by-step explanation:

L+B=-(b)/a.(let L and B be zeroes)

3+root7+3-root7=-b/a

+root7-root7 cancels out

6=-b/a

Therefore b =-6 and a = 1

L*B=c/a

3+root7*3-root7= 9-7=2 so c =2

So you can form and quadratic equation by

ax^2+bx+c = x^2-6x+2