Form the quadratic polynomial whose zeroes are 2+√3 a d 2-√3
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it is given that the zeros of the quadratic polynomial is 2+√3 and 2-√3 .
Sum of zeros = (2+√3+2-√3) = 4 .
Product of zeros = (2+√3)(2-√3)
= (2)^2 - (√3)^2
= 4 -3 = 1
New polynomial ,
P(x) = x^2 - ( sum of zeros ) x + ( product of zeros )
= x^2-4x+1
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Answer:
x²-4x+1=0
Step-by-step explanation:
Let the quadratic polynomial be ax²+bx+c=0 and its zeroes be α and β.
We have
Sum of zeroes=α+β=2+√3+2-√3=4 =-b/a
Product of zeroes=αβ=
(2+√3)(2-√3)=(2)²-(√3)²=4-3=1=c/a
Here, a=1, b=-4 and c=1
So, one quadratic polynomial which fits the given conditions is x²-4x+1=0
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