Question

Form the quadratic polynomial whose zeroes are 2+√6,2-√6​

Answer 1

$\frac{-b}{a} =2+\sqrt{6}+(2-\sqrt{6})\\\frac{-b}{a} =2+\sqrt{6}+2-\sqrt{6}\\\frac{-b}{a} =\frac{4}{1} \\   \\now considering the second statement - -\\\frac{c}{a} = 2+\sqrt{6}(2-\sqrt{6})\\\frac{c}{a} = 4-2\sqrt{6} +2\sqrt{6} -6\\\frac{c}{a} = 4-6\\\frac{c}{a} = \frac{-2}{1}\\\\by considering both a=1 and b=-4 c=-2\\so the eq is \\x^{2} -4x - 2$