Question

Form the quadratic polynomial whose zeroes are 3and1/5

Answer 1

Step-by-step explanation:

the quadratic polynomila with zero's are

${x}^{2} - (a + b)x + ab$

${x}^{2} - (3 + \frac{1}{5} )x + 3 \times \frac{1}{5}$

${x}^{2} - ( \frac{16}{5} )x + \frac{3}{5}$

${x}^{2} - \frac{16}{5} x + \frac{3}{5}$

$\frac{1}{5} (5 {x}^{2} - 16x + 3)$

Answer 2

Answer:

so this is your answer hope you got it