Question

Form the quadratic polynomials whose zeores are
(i) -√2and √2​

Answer 1

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Answer 2

Answer:

${x}^{2} - \sqrt{2x} + \sqrt{2 = 0}$

Step-by-step explanation:

$Let \: \alpha \: and \: \beta \: be \: the \: zeroes \: of \: the \: \\ quadratic \: polynomial$

$We \: know \: that$

${x}^{2} - ( \alpha + \beta )x + ( \alpha \times \beta )$

${x}^{2} - \sqrt{2x} + \sqrt{2 = 0}$

$Hence \: {x}^{2} - \sqrt{2x} + \sqrt{2} = 0 \: \\ is \: the \: required \: \\ quadratic \: polynomial$