Question

Form the quadratic polynomials whose zeroes are
1)-3and2/5

Answer 1

.

Step-by-step explanation:

The sum of the zeros is

=-3+2/5=(-15+2)/5=-13/5

And the product is

=-6/5

Now the quadratic equation is

X^2-(-13/5)X+(-6/5)=0

5X^2+13X-6=0

Answer 2

Answer:

$\huge{\red{\boxed{\boxed{\red{\underline{\green{\sf{5x^{2}+13x-6}}}}}}}}$

Step-by-step explanation:

$\huge{\green{\boxed{\boxed{\green{\underline{\red{\sf{SOLUTION-}}}}}}}}$

$\alpha = - 3 \\ \beta = \frac{2}{5} \\ according \: to \: question \\ (x - \alpha )(x - \beta ) = 0 \\ (x - ( - 3))(x - \frac{2}{5} ) = 0 \\( x + 3)( \frac{5x - 2}{5}) = 0 \\ (x + 3)(5x - 2) = 0 \\ 5 {x}^{2} + 15x - 2x - 6 = 0 \\ {5x}^{2} + 13x - 6 = 0$

$\huge{\red{\boxed{\boxed{\red{\underline{\green{\sf{5x^{2}+13x-6}}}}}}}}$