Question

form the quadratic polynomials whose zeroes are 3_+√2​

Answer 1

Answer:

Step-by-step explanation:

Answer:

Zeros : 3 + √2 ; 3 - √2

General Form of a Quadratic Equation: ax² + bx + c

Here b is the sum of roots, c is the product of roots.

Sum of roots is taken as negative value.

That is,

=> x² - ( sum of roots ) x + product of roots.

According to your question,

Sum of roots = 3 + √2 + 3 - √2

=> Sum of roots = 6

Product of roots = ( 3 + √2 ) ( 3 - √2 )

=> Product of roots = 3² - ( √2 )²

=> Product of Roots = 9 - 2 = 7

Hence on substituting the values we get,

=> x² - ( 6 ) x + 7

=> x² - 6x + 7

This is the required equation.

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