Question

form the quadratic polynomials whose zeroes are -root 2 and root 2​

Answer 1

zeroes are -√2 and √2

sum of zeroes is -√2+√2=0

product of zeroes-√2×√2=-√4=-2

quadratic polynomial

x2-sx+p

x2-0x+(-2)

x2-2

therefore x2 -2 is the required quadratic polynomial

Answer 2

Answer: $x^{2}$ - 2

Step-by-step explanation:

Given - zeroes are -√2 and √2

To find - Quadratic polynomials whose zeroes are -$\sqrt2$ and $\sqrt 2$

Sum of zeroes is -√2+√2=0

Product of zeroes-√2×√2=-√4= -2

x= $\sqrt2$                           x= -√2

x - √2=0                      x + √2= 0

(x - √2) (x + √2)= 0

$x^{2}$ - 2 = 0

Answer = $x^{2}$ - 2

A polynomial whose highest degree monomial is of the second degree is said to be quadratic. A second-order polynomial is another name for a quadratic polynomial. Accordingly, at least one of the variables must be raised to the power of 2, and the powers of the remaining variables must be more than or equal to two but less than -1.

Multivariable quadratic polynomials are possible. The most often employed polynomial, however, is a univariate quadratic polynomial with a single variable. A univariate quadratic polynomial has a parabola as its graph.

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