Question

form the Quadratic polynomials whose zeros are:
1/3 and 1/4​

Answer 1

Answer:

12x^2-7x+1

Step-by-step explanation:

sum of zeroes=-b/a

1/3+1/4= -7/12

product of zeroes= c/a

1/3*1/4= 1/12

then the equation will be

12x^2-7x+1

Answer 2

Answer:

$sum \: of \: roots \: = - ( \frac{1}{3} + \frac{1}{4} ) \\ = - ( \frac{7}{12} ) \\ product \: of \: roots \: = \frac{1}{3} \times \frac{1}{4} \\ = \frac{1}{12} \\ equation \: = > \\ {x }^{2} + (sum \: of \: roots)x + (product \: of \: roots) = 0 \\ x ^{2} - \frac{7}{12} + \frac{1}{12} = 0 \\ 12 {x}^{2} - 7 + 1 = 0 \times 12 \\ = 0$