Question

Forma quadrati polynomial, the sum and product of whose zeros are-3 and 2respectach​

Answer 1

Answer:

LET ALPHA =-3

BETA=2

For a quadratic polynomial

x^2-(alpha+beta)x+ alpha * beta

Put the values,

x^2-(-3+2)x+(-3*2)

x^2-(-1)x+(-6)

x^2+1x-6

Required Polynomial is

$x {}^{2} + x - 6$

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Answer 2

$\huge {\red {\underline {\underline {\mathsf {\blue{answer}}}}}}$

$\boxed{given \: zeroes \: 5 \: and \: - 3}$

$\therefore(x - 5)(x - ( - 3))$

$= > (x - 5)(x + 3)$

$= > x(x + 3) - 5(x + 3)$

$= > {x}^{2} + 3x - 5x - 15$

$= > {x}^{2} - 2x - 15$

so, ur answer is option (b)

$\boxed{{x}^{2} - 2x - 15}$