Question

formal letter to editor for cybercrime​

Answer 1

Answer:

cybercrime ko likhene se koe fayada nahi ha

khud he kuch karo

Answer 2

Given:-

$\sf \dfrac{3}{x + 1 } - \dfrac{1}{2} = \dfrac{2}{3x - 1}$

To Find :-

Value of x

Solution :-

$\pink{ \sf \qquad\leadsto\quad \dfrac{3}{x + 1 } - \dfrac {1}{2} = \dfrac{2}{3x - 1} }$

$\qquad\leadsto\quad\sf \dfrac{3 \times 2 - (x + 1)}{2(x + 1)} = \dfrac{2}{3x - 1}$

$\qquad\leadsto\quad\sf \dfrac{6 - x - 1}{2x + 2} = \dfrac{2}{3x - 1}$

$\qquad\leadsto\quad\sf\dfrac{5 - x}{2x + 2} = \dfrac{2}{3x - 1}$

$\qquad\leadsto\quad\sf (5 - x)(3x - 1) = 4x + 4$

$\qquad\leadsto\quad\sf 15x - 3 {x}^{2} - 5 + x = 4x + 4$

$\qquad\leadsto\quad\sf 16x - 4x - 3 {x}^{2} - 5 - 4 = 0$

$\qquad\leadsto\quad\sf 12x - {3x}^{2} - 9 = 0$

$\qquad\leadsto\quad\sf 3 {x}^{2} - 12x + 9 = 0$

$\qquad\leadsto\quad\sf {x}^{2} - 4x + 3 = 0$

$\qquad\leadsto\quad\sf {x}^{2} - 3x - x + 3 = 0$

$\qquad\leadsto\quad\sf x(x - 3) - 1(x - 3) = 0$

$\qquad\leadsto\quad\sf (x - 1)(x - 3) = 0$

$\:\:\:\:\:\:\:\::\:\implies\:{\underline{\boxed{\frak{\pink{x\:= 1 \: Or\: 3}}}}}\:\bigstar$

$\therefore\:\underline{\textsf{Value of x is \textbf{1 \: Or\: 3 }}}.$