Question

formation of Ethylene in sp2 diagram??​

Answer 1

Answer:

In ethene molecule, the carbon atoms are sp2 hybridized. One unpaired electron in the p orbital remains unchanged. In ethylene, each carbon combines with three other atoms rather than four. There is a formation of a sigma bond and a pi bond between two carbon atoms.

Answer 2

Answer:

Ethene, C2H4

The simple view of the bonding in ethene

At a simple level, you will have drawn ethene showing two bonds between the carbon atoms. Each line in this diagram represents one pair of shared electrons.

Ethene is actually much more interesting than this.

An orbital view of the bonding in ethene

Ethene is built from hydrogen atoms (1s1) and carbon atoms (1s22s22px12py1).

The carbon atom doesn't have enough unpaired electrons to form the required number of bonds, so it needs to promote one of the 2s2 pair into the empty 2pz orbital. This is exactly the same as happens whenever carbon forms bonds - whatever else it ends up joined to.

So the first thing that happens is . .

Promotion of an electron

There is only a small energy gap between the 2s and 2p orbitals, and an electron is promoted from the 2s to the empty 2p to give 4 unpaired electrons. The extra energy released when these electrons are used for bonding more than compensates for the initial input.

The carbon atom is now said to be in an excited state.