Chemistry, asked by gill5796, 11 months ago

Formation of polyethylene from calcium carbide
takes place as follows
CaC₂+2H₂O⟶Ca(OH)₂+C₂H₂
C₂H₂+H₂⟶C₂H₄
nC₂H₄⟶(-CH₂-CH₂-)n*
The amount of polyethylene obtained from 64.1
kg of CaC₂ is
(a) 7 kg (b) 14 kg
(c) 21 kg (d) 28 kg

Answers

Answered by Anonymous

2

Answer:

Explanation:

(a) 7 kg

64g of CaC2 gives 28g of ethylene

∴ 64kg of CaC2 will give 28kg of polyethylene

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