Question

formed.
(a) Nichrome wire of length L' and radius R has resistance of 10 How would the resistance of the
wire change when : :
(i) Only length of the wire is doubled ?
(ü) Only diameter of the wire is doubled ? Justify your answer​

Answer 1

Answer:

i) when the length of the wire is doubled the resistance of the wire will be doubled. as the resistance is directly proportional to length.

ii) when the diameter of the wire is doubled the cross section will be 4 times the previous. so the resistance will be 1/4th of the previous. as resistance is inversely proportional to the resistance.

Answer 2

Answer:

Explanation:

R ∝ L So resistance becomes two times i.e., R = 20 Ω

(ii) R ∝ 1/A ∝ 1/d2 So when the diameter is doubled, resistance becomes one-fourth of the original i.e., R =2.5

Or

R ∝ L So resistance becomes two times i.e.,

R = 20 Ω

(ii) R ∝ 1/A ∝ 1/d2 So when the diameter is doubled, resistance becomes one-fourth of the original i.e., R =2.5ohm