Question

formed by splitting and sliding of large blocks of land

Answer 1

Explanation:

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Answer 2

Explanation:

According to the Question

Firstly we calculate the initial velocity of the car . Using 1st equation of motion

v = u + at

where,

v is the final velocity

a is the acceleration

u is the initial velocity

t is the time taken

Substitute the value we get

:\implies:⟹ 0 = u + (-10) × 5

:\implies:⟹ -u = -50m/s

:\implies:⟹ u = 50m/s

So the initial velocity of the car is 50m/s

Now, calculating the final velocity of the car by using 3rd equation of motion.

v² = u² + 2as

substitute the value we get

:\implies:⟹ 0² = 50² + 2(-10)× s

:\implies:⟹ 0 = 2500 -20s

:\implies:⟹ -2500 = -20s

:\implies:⟹ 20s = 2500

:\implies:⟹ s = 2500/20

:\implies:⟹ s = 125 m

Hence, the distance covered by the car before coming to rest is 125 metres.