former rifle of mass 6 kg A bullet of mass 40 kg is fired with initial velocity of 108 km per hour calculate the initial recoil velocity of the rifle
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m1=6kg
m2=0.40kg
v1=?
v2=108km/hr
u1= 0 becase they are on rest before firing
u2=0
acoording to conservation of momentum
m1u1+m2u2 = m1v1+m2v2
6kg*0+0.40kg*0=6kg*v1+o.40kg*108 (*=multiply)
0+0=6v1+43.2
-43.2 =6v1
-43.2/6=v1
7.2 v1
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m2=0.40kg
v1=?
v2=108km/hr
u1= 0 becase they are on rest before firing
u2=0
acoording to conservation of momentum
m1u1+m2u2 = m1v1+m2v2
6kg*0+0.40kg*0=6kg*v1+o.40kg*108 (*=multiply)
0+0=6v1+43.2
-43.2 =6v1
-43.2/6=v1
7.2 v1
hope it will help you
mark as brainliest
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