Formula 2m1×m2×g/m1+m2 applied for calculating
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So, The Answer Is --) Let m1>m2 and T be the tension in string so there will ... now substitute acceleration in equation 1 or 2 to get T m1g-T =m1a. T =m1(g-a) = m1g- m1(m1-m2)g/(m2.
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here Is yOur Answer..
hope IT'S HELP....!!!
So, The Answer Is --) Let m1>m2 and T be the tension in string so there will ... now substitute acceleration in equation 1 or 2 to get T m1g-T =m1a. T =m1(g-a) = m1g- m1(m1-m2)g/(m2.
#ThnkYou
Follow me (for more help)
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