formula for (a-b-c)²
Answers
Answered by
8
Answer:
➡ Refer to Attachment
Good question
Attachments:
Answered by
1
(a - b - c)²
=> (a)² +(-b)² + (-c)² + 2× [ a×(-b)) + (-b)×(-c) + (-c)×a]
=> a² + b² + c² + 2 [ -ab + bc - ac]
=> a² + b² + c² - 2ab + 2bc - 2ac
HOPE IT HELPS
PLEASE MARK ME BRAINLIEST ☺️
Similar questions