Formula for angle between two tangents drawn to a circle in terms of cos
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Hi. Here's your answer:
Step-by-step explanation:
We know,
The tangents to a circle from an external point are equal.
So, AC=BC
Let the centre be O.
Then, AO=BO(radii of the same circle)
By theorem 10.1, ∠OAC=∠OBC=90°
Thus, in quadrilateral AOBC, ∠A=∠B=90°
We know, ∠A+∠B+∠C+∠O=360°
So, here we conclude that ∠O+∠C=180°_____________(∠O is the angle between two tangents i.e. AC and AB)
So,Formula for angle between two tangents=180°- central angle
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