formula for area of a semicircle,circle,triangle,hexagon,sector,segment,square,rectangle
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Hey mate !!
Here's the answer !!
Area of the shapes are listed below :
Semicircle = πr² / 2
Circle = πr²
Triangle =![\frac{1}{2} * Base * Height \frac{1}{2} * Base * Height](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7B2%7D++%2A+Base+%2A+Height)
Hexagon = 3√3 / 2 * Side²
Sector = Ф / 360° * πr² ( Here Ф = Angle )
Segment = Area of sector - Area of Triangle
= ( Ф / 360° * πr² ) - 1 / 2 * Base * Height
Square = Side²
Rectangle = Length * Breadth
Hope my answer helped you !!
Cheers !!
Here's the answer !!
Area of the shapes are listed below :
Semicircle = πr² / 2
Circle = πr²
Triangle =
Hexagon = 3√3 / 2 * Side²
Sector = Ф / 360° * πr² ( Here Ф = Angle )
Segment = Area of sector - Area of Triangle
= ( Ф / 360° * πr² ) - 1 / 2 * Base * Height
Square = Side²
Rectangle = Length * Breadth
Hope my answer helped you !!
Cheers !!
yashgajra90p7ohq3:
yes
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