Formula for area of triangle in coordinate geometry
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1/2 [x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]
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let ABC be a triangle with vertices qA(x1,y1) B(x2,y2) C(x3,y3)
are(ABC)=1/2(x1(y2-y3)+x2(y3-y1)+x3(y1-y2))
are(ABC)=1/2(x1(y2-y3)+x2(y3-y1)+x3(y1-y2))
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