Question

formula for Calculation of No. of squares in a chess board

and no. of rectangles​

Answer 1

$\huge\star{\tt{\underline{\underline{\red{Answer}}}}}\star$

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Chess Board For n x n sides

No. of squares = $\large \sum_{r=1}^{n} {r}^{2} \frac {n(n+1)(2n+1)}{6}$

No. of rectangles = $\large\sum_{r=1}^{n} {r}^{3} {\frac{n(n+1)}{2}}^{2}$

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Answer 2

Here is your answer user.