formula for ci for 3 successive years with rate x% y% z%. with principal as P.?
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Total Amount based on Compound Interest, A = P(1 + (R/100))^n
Amount at the end of 1st year, A = P(1 + (X/100)) = P1
Amount at the end of 2nd year, A = P1(1 + (Y/100)) = P(1 + (X/100))*(1 + (Y/100)) = P2
Amount at the end of 3rd year, A = P2(1 + (Z/100)) = P(1 + (X/100))*(1 + (Y/100))*(1 + (Z/100)) ——> Answer
Amount at the end of 1st year, A = P(1 + (X/100)) = P1
Amount at the end of 2nd year, A = P1(1 + (Y/100)) = P(1 + (X/100))*(1 + (Y/100)) = P2
Amount at the end of 3rd year, A = P2(1 + (Z/100)) = P(1 + (X/100))*(1 + (Y/100))*(1 + (Z/100)) ——> Answer
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