Formula for finding the sum of an arithmetic progression
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Sn=n/2{2a+(n-1)d}
I hope it helps uu
Answered by
1
Answer:
Step-by-step explanation:
Sn=n/2[2a+(n-1)d]
Or when An is given then
Sn=n/2(a+An)
Where An is the last term
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