Question

Formula for range of projectile motion from a height

Answer 1

Answer:

t\√2g.........................

Answer 2

Answer:

$horizontal \: range \: = \: \frac{u {}^{2} \sin(2 \alpha ) }{g}$

$maximum \: height \: = \: \frac{u {}^{2} \sin {}^{2} ( \alpha ) }{2g}$

Hope it's help's you