Question

formula for sum of consecutive odd numbers of cubes

Answer 1

Answer:

Thus for n odd, n3 is again the sum of the consecutive odd integers from (n2 û n + 1) to (n2 + n û 1). This also can be verified by summing. Figure 1. Base cases for cubes as sums of odd integers: n=2 and n=3.

Answer 2

Answer:

Thus for n odd, n3 is again the sum of the consecutive odd integers from (n2 û n + 1) to (n2 + n û 1). This also can be verified by summing. Figure 1. Base cases for cubes as sums of odd integers: n=2 and n=3.

Step-by-step explanation:

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