formula for x^6+1/x^6
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y = x^6 + 1/x^6 = (x^2)^3 = (1/x^2)^3
since a^3 + b^3 = (a + b)(a^2 - ab + b^2)
y = (x^2 + 1/x^2)(x^4 - 1 + 1/x^4)
since a^3 + b^3 = (a + b)(a^2 - ab + b^2)
y = (x^2 + 1/x^2)(x^4 - 1 + 1/x^4)
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