Question

formula Method 7x + 1 = 6x²​

Answer 1

$-6x^{2} +7x+1=0$

$\frac{-b+or-\sqrt{b^{2}-4ac } }{2a}$

$\frac{-7+or-\sqrt{36+24} }{-12}$

$\frac{-7+or-\sqrt{80} }{-12}$

$\frac{-7+or-4\sqrt{5} }{-12}$

$x=\frac{-7+4\sqrt{5} }{-12} \\or\\x= \frac{-7-4\sqrt{5} }{-12}$