Formula of 1/alpha³+1/beta³ =
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We know that α+β=−ba and αβ=ca.
The sum of the new roots is α+1β+β+1α=−ba+α+βαβ=−ba+−baca=−ba−bc=−bc+abac
The product of the new roots is (α+1β)(β+1α)=αβ+2+1αβ=2+ca+ac=2ac+a2+c2ac=(a+c)2ac .
The new equation is x2+bc+abacx+(a+c)2ac=0⇒acx2+b(a+c)x+(a+c)2=0
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