Question

formula of (-a+b-c)²​

Answer 1

Answer:

${x + y + z}^{2} = x {}^{2} + y {}^{2} + z { }^{2} + 2xy + 2yz + 2zx$

Answer 2

Step-by-step explanation:

(a+b+c)²=a²+b²+c²+2ab+2bc+2ca

put the value of a as (-a) , c as (-c)

it becomes

(-a+b-c)²= a²+b²+c²-2ab-2bc+2ca