Question

Formula of a minus b minus c whole square

Answer 1

Answer:

$Expansion \: of \:\\</p><p>(a-b-c)^{2}\\=a^{2}+b^{2}+c^{2}-2ab+2bc-2ca$

Step-by-step explanation:

Expansion of (a-b-c)²

=[a+(-b)+(-c)]²

/*We know the algebraic identity:

$\boxed {(x+y+z)^{2}\\=x^{2}+y^{2}+z^{2}+2xy+2yz+2zx}$*/

= a²+(-b)²+(-c)²+2a(-b)+2(-b)(-c)+2(-c)a

= a²+b²+c²-2ab+2bc-2ca

Therefore,

$Expansion \: of \:\\</p><p>(a-b-c)^{2}\\=a^{2}+b^{2}+c^{2}-2ab+2bc-2ca$

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Answer 2

The required formula is $(a-b-c)^2=a^2+b^2+c^2-2ab+2bc-2ac$

Step-by-step explanation:

Given : Expression $(a-b-c)^2$

To find : The formula of the expression ?

Solution :

We know the algebraic identity,

$(x+y+z)^2=x^2+y^2+z^2+2xy+2yz+2xz$

Comparing with given expression,

x=a, y=-b, z=-c

Substitute in identity,

$(a-b-c)^2=a^2+(-b)^2+(-c)^2+2(a)(-b)+2(-b)(-c)+2(a)(-c)$

Solve,

$(a-b-c)^2=a^2+b^2+c^2-2ab+2bc-2ac$

Therefore, the required formula is $(a-b-c)^2=a^2+b^2+c^2-2ab+2bc-2ac$

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Formula of a minus b minus c whole square.

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