Question

formula of area of minor segment when angle is greater than 90°​

Answer 1

$The \: degree \: measure \:of \: the \:angle \\at \:the \:centre \:is \:x\degree, \\The \:area \:of \: sector \:is \:\frac{x\degree}{360\degree} \times \pi r^{2}$

$Area \: of \:the \: segment \:APB \\= Area \:of \:the \: sector \:OAPB - Area \:of \:\triangle OAB$

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Answer 2

Answer:

Aare kyu share na kare to accha hai... XD...