Question

formula of arithmetic progression for class 10​

Answer 1

In A.P.

For finding n no. of terms

tn=a+(n-1)d

For finding sum of n no. of terms

Sn=n/2(a+l) or

Sn=n/2[2a+(n-1)d]

here,
Sn=sum of n no. of terms
tn=n no. of terms
a = First term,
d = common difference,
n = number of terms, l=last term

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Answer 2

Here are some important formulae you'll need-

a = First term, d = common difference, n = number of terms, l=last term

an = a + (n-1)d

d = a(n+1) - an

Sn = $\frac{n}{2}$ (2a + (n-1)d)

or

Sn = $\frac{n}{2}$ ( a+l)

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