Question

formula of inner spherical shell
outer spherical shell
CSA
TSA
and volume
correct answers pls ​

Answer 1

Step-by-step explanation:

Outer radius of the spherical lead =

2

24

=12 cm

Radius of the cylinder =

2

16

=8 cm

Since the spherical lead is recasted into the cylinder, their volumes are equal.

Volume of a hollow sphere of outer radius R and inner radius r =

3

4

π(R

3

−r

3

)

Volume of a Cylinder of Radius "R" and height "h" =πR

2

h

Hence,

3

4

π(12

3

−r

3

)=π8

2

×12

Thus 1728−r

3

=576

⇒r

3

=1152

⇒r=

3

1152

=4

3

18

cm

Inner diameter of the spherical lead =2× radius =2×4

3

18

cm =8

3

18

cm