formula of sin^2A-sin^2B
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Answered by
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Answer:
sin^2A - sin^2 B = x^2 - y^2, which can be factorized as (x+y)(x-y).
Step-by-step explanation:
Taking R.H.S.
sin(A+B).sin(A–B)
(sinA.cosB+cosA.sinB).(sinA.cosB-cosA.sinB)
[sin^2(A).cos^2(B)-cos^2(A).sin^2(B)]
[sin^2(A){1-sin^2(B)}-{1-sin^2(A)}sin^2(B)]
[sin^2(A)-sin^2(A)sin^2(B)-sin^2(B)+sin^2(A)sin^2(B)]
sin^2(A)-sin^2(B).
HOPE IT WILL HELP YOU
FROM: ACE7257
Answered by
0
Answer:
sin^2A - sin^2 B = x^2 - y^2, which can be factorized as (x+y)(x-y). Two ways: 1. sin (A - B)
Step-by-step explanation:
hope it helps you
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