Math, asked by sripradapammi44, 1 month ago

formula of sin^2A-sin^2B

Answers

Answered by ace7257
0

Answer:

sin^2A - sin^2 B = x^2 - y^2, which can be factorized as (x+y)(x-y).

Step-by-step explanation:

Taking R.H.S.

sin(A+B).sin(A–B)

(sinA.cosB+cosA.sinB).(sinA.cosB-cosA.sinB)

[sin^2(A).cos^2(B)-cos^2(A).sin^2(B)]

[sin^2(A){1-sin^2(B)}-{1-sin^2(A)}sin^2(B)]

[sin^2(A)-sin^2(A)sin^2(B)-sin^2(B)+sin^2(A)sin^2(B)]

sin^2(A)-sin^2(B).

HOPE IT WILL HELP YOU

FROM: ACE7257

Answered by khayumbasha1969
0

Answer:

sin^2A - sin^2 B = x^2 - y^2, which can be factorized as (x+y)(x-y). Two ways: 1. sin (A - B)

Step-by-step explanation:

hope it helps you

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