formula of sin(A+B)..
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Hey!
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• Formula of sin (α + β) :-
= sin (α + β) = sin α cos β + cos α sin β
= sin (α - β) = sin α cos β -cos α sin β
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Regards :)
Cybary
Be Brainly
_____________________________________________________________________________________________
• Formula of sin (α + β) :-
= sin (α + β) = sin α cos β + cos α sin β
= sin (α - β) = sin α cos β -cos α sin β
_____________________________________________________________________________________________
Regards :)
Cybary
Be Brainly
Answered by
2
Hey there!
Let's deduce this by seeing a small example .There is huge proof for this.
sin ( 90 ) = 1/
sin( 45 + 45 ) = sin45 + sin45 = 1/√2 + 1/√2 = √2 ≠ 1
Sin ( 45 + 45 ) = sin45 * sin45 = 1/√2 *1/√2 = 1/2
If we multiply this by 2 , we may approximately reach there .
sin(45 + 45 ) = 2 sin45 * sin45 = 2 sin45 * cos45 = sin45 cos45 + cos45 sin45 .
This form of sin(A+B) = sinAcosB + cosBsinA eventually goes valid for all values of A & B. So, Hence the formula was deduced.
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sin(A + B) = sinA cosB +cosA sinB
Let's deduce this by seeing a small example .There is huge proof for this.
sin ( 90 ) = 1/
sin( 45 + 45 ) = sin45 + sin45 = 1/√2 + 1/√2 = √2 ≠ 1
Sin ( 45 + 45 ) = sin45 * sin45 = 1/√2 *1/√2 = 1/2
If we multiply this by 2 , we may approximately reach there .
sin(45 + 45 ) = 2 sin45 * sin45 = 2 sin45 * cos45 = sin45 cos45 + cos45 sin45 .
This form of sin(A+B) = sinAcosB + cosBsinA eventually goes valid for all values of A & B. So, Hence the formula was deduced.
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sin(A + B) = sinA cosB +cosA sinB
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